PolarDistort v1.0


 
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Contributor: Daniel Velikov
Photoshop like distortion filter Polar.
Requirements:
9.0, 8.0, 7.1, 7.0 or later
23 May 2015
310
Group {
 name PolarDistort
 selected true
 addUserKnob {20 User l Controls}
 addUserKnob {4 Out l Transform M {'Rectangular to Polar' 'Polar to Rectangular' ''}}
 Out 'Polar to Rectangular'
 addUserKnob {6 Ccc l CheckerSample +STARTLINE}
 Ccc true
 addUserKnob {26 About l '' +STARTLINE T '\nDaniel Velikov  © 2015 \n'}
}
 Input {
  inputs 0
  name Input1
 }
 CheckerBoard2 {
  inputs 0
  name CheckerBoard1
  xpos -516
  ypos 42
 }
 Switch {
  inputs 2
  which {{!Ccc}}
  name Switch2
 }
set N4b281f70 [stack 0]
 Expression {
  temp_name0 rr
  temp_expr0 ((0.5+x)/width)+ax
  temp_name1 gg
  temp_expr1 1-((0.5+y)/height)-ay
  temp_name2 xx
  temp_expr2 gg*sin(pi*2*(1-rr))
  temp_name3 yy
  temp_expr3 gg*cos(pi*2*rr)
  expr0 (1+xx)*.5+(rx-.5)
  expr1 (1+yy)*.5+(ry-.5)
  channel2 {-rgba.red -rgba.green rgba.blue rgba.alpha}
  expr2 0
  channel3 none
  name Expression3
  addUserKnob {20 User}
  addUserKnob {7 ax l Tx}
  addUserKnob {7 ay l Ty}
  addUserKnob {7 rx l Rx}
  rx 0.5
  addUserKnob {7 ry l Ry}
  ry 0.5
 }
push $N4b281f70
 Expression {
  temp_name0 gg
  temp_expr0 (0.5+x)/(width)-.5
  temp_name1 rr
  temp_expr1 (0.5+y)/(height)-.5
  temp_name2 xx
  temp_expr2 sqrt(rr*rr+gg*gg)
  temp_name3 yy
  temp_expr3 'atan2(x-width/2 , y-height/2 )/pi'
  channel0 {rgba.red -rgba.green -rgba.blue none}
  expr0 1-(yy0?1-abs(yy)/2yy/2)
  channel1 {-rgba.red rgba.green -rgba.blue none}
  expr1 (.5-xx)*2
  channel2 {-rgba.red -rgba.green rgba.blue none}
  expr2 0
  expr3 0
  name Expression2
  addUserKnob {20 User}
 }
 Switch {
  inputs 2
  which {{parent.Out}}
  name Switch1
 }
push $N4b281f70
 STMap {
  inputs 2
  uv rgb
  name STMap3
 }
 Output {
  name Output1
 }
end_group
 
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Comments   

 
+2 # Jung Keun Kim 2015-05-26 03:38
you are my hero~!
 
 
# Matt Cameron 2019-04-29 21:23
nice!!!
 
 
# Matt Cameron 2019-04-30 08:54
This one seems broken but the one at the end of this thread is working for me https://community.foundry.com/discuss/topic/99845/rectangular-to-polar-effect
 

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